X^2-15x-940=0

Solution for X^2-15x-940=0 equation:

X^2-15X-940=0

a = 1; b = -15; c = -940;
Δ = b2-4ac
Δ = -152-4·1·(-940)
Δ = 3985
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-15)-\sqrt{3985}}{2*1}=\frac{15-\sqrt{3985}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-15)+\sqrt{3985}}{2*1}=\frac{15+\sqrt{3985}}{2}
$